Find the magnitude of two forces such that if they act at right angle their resultant is 50kN but if they act at 45 degree their resultant is 30kN.
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Explanation:
Let say two vectors
→
P
and
→
Q
are represented by the two sides of a triangle with an angle between them, then the resultant vector is represented by the third side of the triangle in both magnitude and direction.
In any triangle, the magnitude of the third side is given by ( using trigonometry )
R
=
√
P
2
+
Q
2
+
2.
|
P
|
.
|
Q
|
cos
θ
, where
θ
is the angle between the two vectors
→
P
and
→
Q
.
We will apply this law to solve the question.
Answer and Explanation:
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0
Explanation:
this is the solution....
F1=1334.73
F2= -847.64
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