find the magnitude of two forces such that if they act right angle their resultant is root of 10 Newton but if they Act at 60 degree their resultant is root of 13 Newton.
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Answer:
F1 = 3N ,and F2 = 1 N
Explanation:
Let the forces be F1 and F2
F1^2 + F2^2 = 10
as the angle between them is 90 degrees
when angle is 60
F1^2 + F2^2 + 2 * F1 * F2 * cos(60)=13
10 + F1 * F2=13
3 = F1 * F2
(F1 + F2)^2 = F1^2 + F2^2 + 2 * F1 * F2 = 10 + 6 = 16
F1 + F2 = 4 - (1)
F1 - F2 = √( ( F1 + F2)^2 - 4F1 * F2) = 2 - (2)
from eq.(1) and (2) We get
F1 = 3N ,and F2 = 1 N
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