Physics, asked by khadijakazmi123, 7 months ago

find the magnitude of two like parallel force acting at a distance of 1m apart which are equivalent to a force of 30 N acting at a distance of 0.2 m from one of the forces

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Answered by anshikasaklani08

Answer:

Two like parallel forces 20 N and 30 N act at the ends A and B of a rod 1.5 m ... Thus the point is (1.5 - x) m far from the point B. Thus, using the formula Torque = Distance x Force acting

Explanation:

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find the magnitude of two like parallel force acting at a distance of 1m apart which are equivalent to a force of 30 N acting at a distance of 0.2 m from one of the forces​

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find the magnitude of two like parallel force acting at a distance of 1m apart which are equivalent to a force of 30 N acting at a distance of 0.2 m from one of the forces