find the mass of 10 moles of methanol (ch3oh). given atomic masses of c=12u,h=1u,o=16u
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Mass = molar mass *moles
m =M*n
=(12+3*1+16+1)*10
= 32u*10
= 320 g
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Given:
The moles of methanol = 10.
Atomic masses of carbon, hydrogen, oxygen = 12u, 1u, 16u respectively.
To find:
The mass of 10 moles of CH3OH.
Solution:
The molecular mass of methanol (CH3OH) is,
CH3OH = 12 + 3 x 1 + 16 + 1
= 32 grams.
Therefore, the molecular mass of methanol is 32 grams.
As we know, the molecular mass of a substance is equal to one mole of a substance.
Hence, 1 mole of methanol = 32 grams
Therefore 10 moles of methanol is equal to 32 x 10 = 320 grams.
Hence, the mass of 10 moles of methanol is 320 grams.
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