Question

Find the mass % of 6g sodium hydroxide dissolved in 50g of water​

Answer 1

Answer:

Total mass=6g NaOH + 50g water

=56g

Mass of water 50g

Mass percentage=

=(grams of solute/grams of solution)×100

=(6/56)×100

=0.1074×100

=10.74%

Hope it helps you!

Answer 2

Answer:

The mass percent of 6g of sodium hydroxide dissolved in 50g water is, m% = 10.74%

Explanation:

The usage of mass % is another technique to express the composition of a solution mixture.

• It refers to the amount of solute (in grams) in a 100 gm solution.

Given that the mass of NaOH is 6 gm and water is 50 gm

Therefore,

The total mass of solution = 6 g $NaOH$ +50 g $H_{2}O$= 56 gm

Hence,

$Mass percent= \frac{Mass of solute}{Mass of solution}$  × 100 mass percent

                        $= \frac{6 }{56} * 100$  

                        = 10.74 %