Find the mass of a 3.5 m long lead pipe, if the external diameter of the pipe is 2.4 cm, thickness of the metal is 2 mm and the mass of 1 cm³ of lead is 11.4 grams.
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Answer:
The Mass of the lead pipe is 5.518 kg .
Step-by-step explanation:
SOLUTION :
Given :
Length of pipe, h = 3.5 m = 3.5 × 100 = 350 cm
[1m = 100 cm]
External diameter of the pipe= 2.4 cm
External radius of the pipe, R = 2.4/2= 1.2 cm
Thickness of pipe = 2 mm = 2/10 = 0.2 cm
[1 mm = 1/10 cm]
Internal radius of the pipe, r = External radius of the pipe - Thickness of pipe
r = 1.2 - 0.2 = 1 cm
Volume of the pipe , V = π(R² - r²) h
V = 22/7 (1.2² - 1²)350
V = 22 (1.44 - 1) 50
V = 22 × 0.44 × 50
V = 484 cm³
Volume of the pipe = 484 cm³
Mass of 1 cm³ pipe = 11.4 g
Mass of 484 cm³ pipe = 484 × 11.4 = 5517.6 g = 5517.6/1000 kg = 5518/1000 = 5.518 kg
[1g = 1/1000 kg]
Hence, the Mass of the lead pipe is 5.518 kg .
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