Find the mass of a piece of iron that occupies a volume of 200 cm3, given that the density of iron is 7.8 g/cm3
Answers
Provided that:
- Volume = 200 cm cube.
- Density = 7.8 g/cm cube.
To calculate:
- The mass
Solution:
- The mass = 1560 g
Using concept:
- Density formula
Using formula:
- D = M/V
Where, D denotes density, M denotes mass and V denotes volume.
Required solution:
→ Density = Mass/Volume
→ D = M/V
→ 7.8 = M/200
→ 7.8 × 200 = M
→ 1560 = M
→ M = 1560 g
→ Mass = 1560 g
- The mass of piece of iron is 1560 grams.
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- Find the mass of a piece of iron that occupies a volume of 200 cm3, given that the density of iron is 7.8 g/cm3
- A piece of iron occupies a volume of 200cm³
- The density of the iron piece is 7.8 g / cm³
- The measure mass of the piece of the iron
→ Mass : Mass is defined as the quantitative measure of inertia
→ Volume : Volume is the space occupied by and object
→ Density : Density describes the package of the molecules in volume by an object , i.e ; Mass per Unit Volume
- The mass of the iron piece is 1560 grams (or) 1.56 kg
★ Now as we have been provided with the density of the of the object where the object in the above case is considered to be the piece iron .We also have the measure of the volume and the density of the iron piece so , let's substitute the values in the formula above and find the mass of the iron
- Density ( D ) = 7.8 9/cm³
- Volume ( V ) = 200cm³
By applying the values we get the result ;
✒ Mass = 1.56 kilograms
Henceforth the mass of the object is 1560 grams
- The mass of the iron piece is 1560 grams (or) 1.56 kg
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