Question

find the mass of Na2Co3 present in 100ml of 3M solution​

Answer 1

Answer:

M=no. of moles of solute /volume of solution in L

No of moles = M*volume of solution in L

=3*0.1 (1L=1000ml)

=0.3 moles

Wt. Of Na2CO3 =no of moles * molecular mass of Na2CO3

=0.3 *106

=31.8 g

Hope this helps...

Answer 2

The mass of sodium carbonate in the solution is 31.8 grams

Explanation:

To calculate the mass of sodium carbonate, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 3 M

Molar mass of sodium carbonate = 106 g/mol

Volume of solution = 100 mL

Putting values in above equation, we get:

$3M=\frac{\text{Mass of sodium carbonate}\times 1000}{106\times 100}\\\\\text{Mass of sodium carbonate}=\frac{3\times 106\times 100}{1000}=31.8g$

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