find the mass of Na2co3 present in 100ml of 3M solution
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the answer is
=M=no. of moles of solute /volume of solution in L
No of moles = M*volume of solution in L
=3*0.1 (1L=1000ml)
=0.3 moles
Wt. Of Na2CO3 =no of moles * molecular mass of Na2CO3
=0.3 *106
=31.8 g
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