Question

Find the mass of NaOH present in 250ml of a seminormal solution.

Answer 1

Answer:

Normality = gram equivalent weight /volume

Explanation:

Answer 2

Answer:

The mass of NaOH present in 250ml of a semi normal solution is 5 grams.

Explanation:

Normality is defined as the number of gram equivalent weight of solute per liter of solution.

Given,

Volume of NaOH = 250 ml

1 liter = 1000 ml

The formula for Normality is given as

$Normality = \frac{Weight}{Equivalent weight}$ × $\frac{1000}{V_{ml} }$   ......................(1)

                 = $\frac{Weight * n factor }{M}$ ×  $\frac{1000}{V_{ml} }$

$Normality = \frac{number of moles * n factor * 1000}{V_{ml} }$  .................(2)

The normality of NaOH is $\frac{1}{2}$

n factor = 1

Substitute the values in equation (2) and find the Number of moles:

$\frac{1}{2} = \frac{W}{40} * 1 * \frac{1000}{250}$

Weight = 5

Mass of NaOH = 5  grams

Therefore mass of NaOH present in 250 ml of seminormal solution is 5 grams.

Answer = 5 grams.

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