find the mass of sugar required to prepare iths 10% solution in 250 grams of solution
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Answer:
Explanation:
25 grams of sugar is required to prepare its 10% solution in 250 g solution.
Explanation:
10% solution means that 10 g of solute ion 100 grams of solution.
Here we are have to prepare 250 grams of sugar solution which should be of 10%.
Required percentage of sugar solution,(w/w %) = 10%
Mass of the solute = x
Mass of the solution = 250 g
w/w\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100w/w%=
Mass of solution
Mass of solute
×100
10\%=\frac{x}{250 g}\times 10010%=
250g
x
×100
x = 25 g
Mass of solution = Mass of solute + Mass of solvent
Mass of solvent = 250 - 25 g = 225 g
We need 25 grams of sugar which we will be dissolving in 225 grams of water to prepare 10% sugar solution.
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