English, asked by nezianyirenda, 8 months ago

Find the maxima and minima for y=x³-1.5x²

Answers

Answered by tanejakca
0
Dy/ dx = 3x^2-3x
=3x(x-1)
Put dy/dx=0
So x=0 & x=1
Double derivative =6x-3
At x=oइस —3 thus maximum
At x=1is 3 thus minimum
Answered by ArghyaPratim
0

Explanation:

f(x) = x³ - 1.5x²

diff. both sides wrt x

f'(x)= 3x² - 3x

putting f'(x)= 0

3x² - 3x= 0

3x(x -1) = 0

x=1 , x= 0

Now again diff. , f"(x) = 6x - 3

Putting x=0, f"(x)= -3 is a point of local maxima

f(x) = 0³ - 1.5.0² = 0

Putting x=1, f"(x) = 3 is a point of local minima

f(x)= 1³ - 1.5.1² = -0.5

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