Find the maximum and minimum value of the function y=x^3-3x^2+6
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dy/dx =3x^2-6x put this equal to 0 ,then find x which is 2
max value is max value is 6 and min value is 2 max value is attains when x=0 which we cancelled in dy/dx eqn HOPE This Helps You
max value is max value is 6 and min value is 2 max value is attains when x=0 which we cancelled in dy/dx eqn HOPE This Helps You
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