Find the maximum and minimum value of the polynomial.12x^5 - 45x^4 - 20x ^3 +90x^2
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Step-by-step explanation:



How do you find the inflection points off(x)=12x5+45x4−80x3+6?
Calculus Determining Points of Inflection for a Function
1 Answer

MoominDave
Jun 22, 2018
Maximum: x=-4
Inflection: x=0
Minimum: x=1
Explanation:
In general, this is a hard problem for a quintic equation. But this particular quintic has some missing low order terms that help us a great deal.
To find the inflection and turning points of f(x), we follow the usual procedure and set f'(x)=0.
f(x)=12x5+45x4−80x3+6 so
f'(x)=60x4+180x3−240x2
Now this is a quartic equation. A full "solution by radicals" of the quartic is known, but it is long and complex (and painful to perform!). Fortunately, we can factorise this equation:
f'(x)=60x2(x2+3x−4)=60x2(x+4)(x−1).
So f'(x)=0⇒x=-4, 0, or 1.
To categorise these consider the second derivative:
f''(x)=240x3+540x2−480x=60x(4x2+9x−8)
f'