find the maximum and minimum value of y=4x^2-4x+7
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4
Answer:
6
Explanation:
4x²-4x+7
a=4,b=-4,c=7
Maximum or minimum value=4ac-b²/4a
Maximum or minimum value=4×4×7-(-4)²/4×4
Maximum or minimum value=112-16/16=96/16=6
Answered by
7
Answer:the answer is in the photo attached ask me if u have further doubts
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