Question

find the maximum height of a body if it thrown vertically upwards 30m/sec

Answer 1

hopes it helps
$maximum \: ht \: is \: given \: by \: = \frac{ {u}^{2} }{2g} \\ h(max) = \frac{30 \times30 }{2 \times 10} = \frac{900}{20} = 45m$