Find the maximum number of possible real roots for the given equation if the base is non-negative. (x ^ 2 - 6x + 5) ^ (x ^ 2 - 6x + 9) = 1 a. 1 b. 2 C. 3 d. 4
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Answered by
0
Answer:
12345678901234567890
Answered by
1
Answer:
The correct answer is D. 4
Step-by-step explanation:
(x²-6x+5)(x²-6x+9)=0
=> (x² -5x-x+5)(x²-2×3×x+3²)=0
=> (x-5)(x-1)(x-3)²=0
That means , x= 1,5,3,3
Real roots are 1,5,3,3
Option D. is the correct Answer
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