Find the maximum perimeter of a right triangle with hypotenuse 12cm
jsdcorreo:
28.9705627485 cm -- http://triancal.esy.es/?g=3&c=12
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If the hypotenuse is 12, then lengths of the legs are:
a = 12sinΘ
b = 12cosΘ
The perimeter of the triangle is:
P = 12 + 12(sinΘ + cosΘ)
dP/dΘ = 12(cosΘ - sinΘ) = 0
cosΘ = sinΘ
tanΘ = 1 ==> Θ=45°
the sum of the angles of a triangle is always 180. the third unknown angle is 180 - 90 - 45 = 45.
The three angles of the triangle which maximize the perimeter of a right angle for a given hypotenuse are, 90°, 45°, and 45°.
hope it helps then plzz mark it as brainliest
a = 12sinΘ
b = 12cosΘ
The perimeter of the triangle is:
P = 12 + 12(sinΘ + cosΘ)
dP/dΘ = 12(cosΘ - sinΘ) = 0
cosΘ = sinΘ
tanΘ = 1 ==> Θ=45°
the sum of the angles of a triangle is always 180. the third unknown angle is 180 - 90 - 45 = 45.
The three angles of the triangle which maximize the perimeter of a right angle for a given hypotenuse are, 90°, 45°, and 45°.
hope it helps then plzz mark it as brainliest
Answered by
1
HEY MATE HERE IS YOUR ANSWER--
If the hypotenuse is 12, then lengths of the legs are:
a = 12sinΘ
b = 12cosΘ
The perimeter of the triangle is:
P = 12 + 12(sinΘ + cosΘ)
dP/dΘ = 12(cosΘ - sinΘ) = 0
cosΘ = sinΘ
tanΘ = 1 ==> Θ=45°
the sum of the angles of a triangle is always 180. the third unknown angle is 180 - 90 - 45 = 45.
The three angles of the triangle which maximize the perimeter of a right angle for a given hypotenuse are, 90°, 45°, and 45°.
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