Find the maximum speed at which a car can take turn round a curve of 20m radius on a level road if the coefficient of friction between the tyres and the road is 0.5.
Take g = 10 m/s².
Answers
Answered by
17
✨ HERE IS YOUR ANSWER ✨
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➡ Given :-
r = 20m
µ = 0.5
g = 10 m/s²
➡ To find :-
v = ?
➡ SOLUTION :-
➡ mv²/r = f = µR = µmg
➡ v = √µrg
= √0.5 × 20 × 10
= √100
= 10 m/s
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✨THANKS.✨
❤❤HOPE IT HELPS YOU.❤❤
----------------;)-------------------;)-------------------------
----------------;)-------------------;)-------------------------
➡ Given :-
r = 20m
µ = 0.5
g = 10 m/s²
➡ To find :-
v = ?
➡ SOLUTION :-
➡ mv²/r = f = µR = µmg
➡ v = √µrg
= √0.5 × 20 × 10
= √100
= 10 m/s
----------------;)-------------------;)-------------------------
----------------;)-------------------;)-------------------------
✨THANKS.✨
❤❤HOPE IT HELPS YOU.❤❤
Answered by
4
According to question we have given;
Radius (r) = 20 m
μ = 0.5
g = 10 m/s² (given)
We have to find v.
Formula used is;
mv²/r = f
Now f = μR = μmg
mv²/r = μmg
v = √μrg
v = √0.5 × 20 × 10
v = √100
v = 10 m/s
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