Question

find the maximum value of 16x-13-4x^2
$16x - 13 - 4x {}^{2}$

Answer 1

Answer:3

Step-by-step explanation:let y=16x-13-4x^2

dy/dx=16-8x

Explaination by coordinate:The equation of y is a parabola with coefficient of x^2 negetive so the point at which the slope is zero is maxima therefore at x=2 we get maxima ,i.e., y=16*2-13-4*2^2=32-13-16=3

General explanation: dy/dx =0 so x=2 is a point of extremity and we get d2y/dt2 =-8 so it will have only a maximum value as the slope continuously decreases and that is at x=2 so the answer is y=3

Answer 2

Answer:3

Step-by-step explanation: