Question

find the maximum value of logx /x​

Answer 1

Answer:

Substituting x = e sets the second term to zero, and the first term is negative. So x = e is a maximum

Answer 2

Answer:

(log x)/x = (log x)/(log [math]10^{[/math]x}}) [Assuming the log is to the base 10]

This is equal to log of ( x to the base [math]10^{[/math]x}})

Which is (1/x) log x

That is log (xth root of x)