Math, asked by khairaparam5231, 10 months ago

Find the maximum value of n such that 671! Is perfectly divisible by 45n.

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Answered by Anonymous

Step-by-step explanation:

Find the maximum value of n such that 671! is perfectly divisible by 45n. We will count the number of 32 and 5 in 671!, and which one is lesser in number would be the answer. 165 will be the answer because 32 is lower in number than 5.

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