Find the mean, median, and mode
No. of
centuries
5 10 15 20 25
No. of
cricketers
56 23 39 13 8
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Answers
Answer:
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Step-by-step explanation:
No.of centuries=5,10,15,20,25,
No.of cricketers=56,23,39,13,8
No.of frequency=56,79,118,131,139
To find the mean we will add up total no. of centuries,then devide the total no. of cricketers.
so,
Mean [50x56+10x23+15x39+20x13+25x8]/56+23+39+13+8
Mean=(280+230+585+260+200)/139=1555/139=11.18
As we can see that the no. of centuries by the greatest no. of cricketers are 5,so,the mode will be 5
As we can see that the no. of centuries by the greatest no. of cricketers are 5,so the mode will be 5
As we can see there are 139 cricketers,arranged in increasing order of their number of centuries.
So, the middle one will be (39+1)/2=140/z=70th cricket in the list
So,the median will be the no. of centuries corresponding to 70,i.e.10.
Therefore,median is 10.
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