Math, asked by ashish16554, 4 months ago

find the mean of first ten consecutive positive integers.​

Answers

Answered by Anonymous
6

Answer: 55/10 or 5.5

Answer: 55/10 or 5.5Solution:

Answer: 55/10 or 5.5Solution:By definition,

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)=( 10x11)/2 = 5x11 = 55

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)=( 10x11)/2 = 5x11 = 55Therefore,

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)=( 10x11)/2 = 5x11 = 55Therefore,Mean of the integers from 1 to 10 = 55/10 = 5.5 (Proved)

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)=( 10x11)/2 = 5x11 = 55Therefore,Mean of the integers from 1 to 10 = 55/10 = 5.5 (Proved)An Interesting Observation Here Is:

Answer: 55/10 or 5.5Solution:By definition,Mean or Arithmetic Mean of the integers from 1 to 10= (Sum of the integers from 1 to 10)/(number of integers)Number of integers= 10Sum of the integers from 1 to 10 = N(N+1)/2 (where N = number of integers)=( 10x11)/2 = 5x11 = 55Therefore,Mean of the integers from 1 to 10 = 55/10 = 5.5 (Proved)An Interesting Observation Here Is:5.5 = (1+10)/2 = Mean of the first and last number of the A.P. This provides a quick method of calculation for the Mean of an A.P. without the need of going through the steps we have done above.

Answered by Anonymous
6

Answer:

method 1 =

=1+2+3+4+5+6+7+8+9+10/10

=55/10

=5.5

method 2=

first number + last number /2

1+10/2

11/2

5.5

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