find the mean proportional of X + Y upon x minus y and x square minus y square upon x square y square
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Let the third proportional to (x² - y²) and (x - y) be P.
Therefore, (x² - y²), (x - y) and P are in proportion.
=> (x² - y²) : (x - y) = (x - y) : P
=> (x² - y²)/(x - y) = (x - y)/P
=> P = (x - y)²/(x² - y²)
=> P = (x - y)(x - y)/(x + y)(x - y)
=> P = (x - y)/(x + y).
Therefore, the third proportional to (x² - y²) and (x - y) is (x - y)/(x + y).
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Actually answer is X+y Upon XY
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Answer:
x+y/x-y
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