find the mean translational kinetic energy of molecules of helium at 27°C.Kb=1.38÷10^23J/k
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mean translation kinetic energy =3/2kT
=3/2 x 1.38 x 10^-23 x 300
=450 x 1.38 x 10^-23 joule
=6.21 x 10^-21 joule
=3/2 x 1.38 x 10^-23 x 300
=450 x 1.38 x 10^-23 joule
=6.21 x 10^-21 joule
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