Find the measure if an angle
7 times its complement is 10 degree less than 3 times its supplement.
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let the angle be x°
ATQ
7(90-x) = 3(180-x) -10
630-7x = 540 -3x -10
7x -3x =630-540+10
4x = 100
x = 100/4
x=25°
ATQ
7(90-x) = 3(180-x) -10
630-7x = 540 -3x -10
7x -3x =630-540+10
4x = 100
x = 100/4
x=25°
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