Find the measure of a side of a rhombus if its diagonal measure 35 cm and 28cm
Answers
Answered by
50
Let ABCD be a rhom. with O as intersection of diagonals.
And we know that diagonal bisect each other
>OA=1/2AD=35/2=17.5
>OB=1/2BC=28/2=14
By Pythagoras Theorem
AB^2=OA^2+OB^2
AB^2=17.5^2+14^2
AB^2=502.25
AB=√502.25
AB=22.14
And we know that diagonal bisect each other
>OA=1/2AD=35/2=17.5
>OB=1/2BC=28/2=14
By Pythagoras Theorem
AB^2=OA^2+OB^2
AB^2=17.5^2+14^2
AB^2=502.25
AB=√502.25
AB=22.14
Answered by
20
Please see the attachment
Attachments:
Similar questions