find the measure of acute angle of a right angled isosceles triangle
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Answered by
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Since, the triangle is isosceles
Its both angles other than right angle are equal.
Let each of equal angles be a
By angle sum property of triangle,
a + a + 90 = 180
=> 2a = 90
=> a = 45
Measure of each acute angle = 45°
Its both angles other than right angle are equal.
Let each of equal angles be a
By angle sum property of triangle,
a + a + 90 = 180
=> 2a = 90
=> a = 45
Measure of each acute angle = 45°
Answered by
46
Here is your solution
Given :-
ABC is a right isosceles Triangle .
in which
Two sides are equal
I. e
AC = BC
hence
∠A=∠B
∠ACB = 90°
we know that
sum of triangle is 180°
∠A+∠B+∠c = 180
∠A+∠B+90° = 180
∠A+∠A+90° = 180° [ ∠A = ∠B Given ]
2∠A+90° = 180°
2∠A = 180°-90°
∠A = 90°/2
∠A=45°
Hence
measure of acute angle of a right angled isosceles triangle is 45°
Hope it helps you
Given :-
ABC is a right isosceles Triangle .
in which
Two sides are equal
I. e
AC = BC
hence
∠A=∠B
∠ACB = 90°
we know that
sum of triangle is 180°
∠A+∠B+∠c = 180
∠A+∠B+90° = 180
∠A+∠A+90° = 180° [ ∠A = ∠B Given ]
2∠A+90° = 180°
2∠A = 180°-90°
∠A = 90°/2
∠A=45°
Hence
measure of acute angle of a right angled isosceles triangle is 45°
Hope it helps you
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