Question

Find the measure of all the angles of parallelogram,if one angle is 24 less than twice the smallest angle.

Answer 1

We know that Sum of adjacent sides of a parallelogram = 180

Let the smallest angle of the parallelogram be x.

Then the other angle will be (2x-24).

x + (2x - 24) = 180

3x - 24 = 180

3x = 204

x = 68.

Then the other angle will be 2(68) - 24 = 112.

The angles are 68,112.

Answer 2

Let the smallest angle be 'x'

The other angle = 2x-24

in a parallelogram, opposite angles are equal

∴x+x+2x-24+2x-24=360

  6x-48=360

  6x=360+48

  x=408/6

 ∴x=68°

  the angles are 68°,112°,68°,112°