find the measure of an angle that is double its supplement
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Answered by
42
Let the first angle be x and second amgle be 2x
Measure of supplementary angles is 180°
A/q,
x + 2x = 180°
3x = 180°
x =
x = 60
1st angle => x => 60°
2nd angle => 2x => 2 × 60 => 120°
Measure of supplementary angles is 180°
A/q,
x + 2x = 180°
3x = 180°
x =
x = 60
1st angle => x => 60°
2nd angle => 2x => 2 × 60 => 120°
BrainlyPrincess:
:-)
Answered by
27
let the first angle x and second angel 2x
now,
ㄥx + ㄥ2x = 180°
ㄥ3x = 180°
x = 60
so, angle x = 60°, angle 2x => 2×60 = 120°
I hope it's help you
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