Math, asked by shreyagopikannan7023, 1 year ago

find the measure of each angle of a parallelogram, if one of its angles is 15 less than twice the smallest angle

Answers

Answered by tadikondakhajit
0

Answer:

117

Step-by-step explanation:

15 +x-2 +15 +x-2=360

30+2x-4=360

26+2x=360

2x=360-26

2x=234

x=234÷2

x= 117

Answered by paritoshveerpd77uv
1

Answer:

65, 65, 115, 115

Step-by-step explanation:

In a parallelogram, the adjacent angles are supplementary; their sum is 180°. The opposite angles are equal.

Let the smallest angle be x. Then the adjacent angle will be 2x-15. They are mutually supplementary.

x + 2x - 15 = 180°

3x = 195°

x = 65°

Its supplement will be 115°

All angles will be 65°, 65°, 115°, 115°

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