Math, asked by panchalgayatri1611, 6 months ago

find the measure of each angle of a parallelogram, if one of its angles is 30 less than twice the smallest number ​

Answers

Answered by manoj1835
1

Answer:

30,150,30,150

Step-by-step explanation:

sum of all angles of parallelogram=360

opposite angles of parallelogram are equal

let the another angle be x

30+x+30+x=360

60+2x=360

2x=360-60

2x=300

x=300/2

x=150

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