Question

find the measure of each angle of a parallelogram, if one of its angles is 30 degrees less than the twice smallest angle ?

Answer 1

Let one angle be x
and another angle be

x = 2(x - 30)

x= 2x - 60

-x = -60

Hence one angle is 60°

Now in parall. opposite angles are equal so two angles are 60° each.

Sum of adjacent angle would be 180°

x + 60° = 180°

x = 180° - 60° = 120°


Hence angles are 60°, 120°, 60° ,120°



Thanks

Answer 2

hii


please mark as brainliest