Find valu of x
x^4-31²+150=0
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ok!
|x^2 + 16| - 5 = 27
It means that either (x^2 + 16) - 5 = 27 or (x^2 + 16) - 5 = - 27
Solving the first of these, x^2 + 16 = 32 => x^2 = 16 => x = -4 or 4
Solving the second, x^2 + 16 = -22 => x^2 = -6 => x = \sqrt{6}, -\sqrt{6}
Using statement 1 alone, we don't get a unique answer.
Using Statement 2 alone,
x^2 = 8x - 16 => x^2 - 8x + 16 = 0 => x^2 - 4x - 4x + 16 = 0 => (x-4) (x-4) = 0
This gives x = 4 and |x| = 4.
So, statement 2 alone is sufficient but statement 2 alone is not sufficient
|x^2 + 16| - 5 = 27
It means that either (x^2 + 16) - 5 = 27 or (x^2 + 16) - 5 = - 27
Solving the first of these, x^2 + 16 = 32 => x^2 = 16 => x = -4 or 4
Solving the second, x^2 + 16 = -22 => x^2 = -6 => x = \sqrt{6}, -\sqrt{6}
Using statement 1 alone, we don't get a unique answer.
Using Statement 2 alone,
x^2 = 8x - 16 => x^2 - 8x + 16 = 0 => x^2 - 4x - 4x + 16 = 0 => (x-4) (x-4) = 0
This gives x = 4 and |x| = 4.
So, statement 2 alone is sufficient but statement 2 alone is not sufficient
maya8888:
How?
Answered by
1
I think it's 5.33 6484 hope my answer satisfies you please mark my answer as brainliest answer sorry for the wrong answer
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