Question

Find the measure of each angle of a parallelogram, if one of its angles is 30 degree less than twice the smallest angle

Answer 1

Let the smallest angle=x Second angle = 2x-30 Sum of two adjacent angles in a parallelogram=180 x+2x-30=180 3x=180+30 3x=210 x=210/3 x =70 Second angle = 2x-30=2*70-30=110 Therefore Four angles of the parallelogram are 70, 110,70,110

Answer 2

Answer is in attachment.

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