Question

Find the measure of each exterior angle and interior angle of a regular 10 sided polygon

Answer 1

Sum of interior angles of a polygon

=(n-2)180

=8*180

=1440°

each angle=1440/10

=114°

Exterior angle=360-114

=246°

Answer 2

Solution:–

Substituting n = 10 in the formula

$(x = \dfrac{360°}{n})$ for exterior angle, we get

.

$x = \dfrac{360 \degree}{n} = \dfrac{360 \degree}{10} =36 \degree$

.

Exterior angle of a 10-sided regular polygon = 36°

Interior angle of a 10-sided regular polygon = 180° – 36° = 144°

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Answer:–

Exterior angle = 36°

Interior angle = 144°

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