Question

Find the measure of each interior angle of a regular polygon with 10 sides.

Answer 1

SoluTion :-

$\boxed {\rm {Sum \ of \ the \ interior \ angles \ of \ a \ regular \ polygon \ of \ n \ sides = (n-2) \times 180 }}$

A regular polygon with 10 sides is a decagon.

Here, n = 10

Thus,

(n - 2) × 180

= (10 - 2) × 180

= 8 × 180 = 1440

To find the measure of each side, divide it by n,

$\sf {Measure \ of \ each \ interior \ angle = \dfrac{1440}{10} = 144^{o}}$

Thus, answer = 144°

Answer 2

Hi there!

☆ GIVEN :-

Polygon with 10 sides.

☆ TO FIND :-

Interior Angle.

☆ FORMULA USED :-

$\bf\red{(n - 2) \times 180}$

n = sides = 10.

So,

$\bf\blue{(10 - 2) \times 180}$

$\bf\pink{8 \times 180}$

$\bf\green{1440}$

So, the answer is 1440°.