find the measure of each interior angle of a regular polygon having 10 sides
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Answered by
32
#AlexaRousey here!!
Interior angle of a regular polygon having n sides = (n-2)180°/n
= (10-2)*180°/10
= 8*180/10
= 8*18°
= 144°
Hope it helps uh!!
Interior angle of a regular polygon having n sides = (n-2)180°/n
= (10-2)*180°/10
= 8*180/10
= 8*18°
= 144°
Hope it helps uh!!
Answered by
8
Here is your answer!
Number of sides of polygon=10
So,Measure of each interior angle=(10-2)×180°/10
= 8×180°/10
= 144°
The formula used here is {(n-2)×180°/10}.
Hope it helps!
Please mark as BRAINLIST and FOLLOW ME
:)
Number of sides of polygon=10
So,Measure of each interior angle=(10-2)×180°/10
= 8×180°/10
= 144°
The formula used here is {(n-2)×180°/10}.
Hope it helps!
Please mark as BRAINLIST and FOLLOW ME
:)
Tanmaykaushik8181:
please mark as BRAINLIST
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