find the measure of each of angles BOC,AOC andAOD
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Angle BOC =
COB + BOD =180 ( LINEAR PAIR)
COB = 180 - 40 ( BOD = 40 DEGREE GIVEN)
COB = 140 DEGREE.
ANGLE AOC = ANGLE BOD
AOC = 40 DEGREE
ANGLE AOD
ANGLE AOD + ANGLE BOC = 180 DEGREE
( LINEAR PAIR OF ANGLES)
AOD = 180-40
AOD = 140. DEGREE
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COB + BOD =180 ( LINEAR PAIR)
COB = 180 - 40 ( BOD = 40 DEGREE GIVEN)
COB = 140 DEGREE.
ANGLE AOC = ANGLE BOD
AOC = 40 DEGREE
ANGLE AOD
ANGLE AOD + ANGLE BOC = 180 DEGREE
( LINEAR PAIR OF ANGLES)
AOD = 180-40
AOD = 140. DEGREE
MARK ME AS A BRAINLIST
Sudhir1188:
thanks
Answered by
2
In the fig.
Angle BOD+angle BOC=180°
angle BOC=180°-Angle BOD
BOC=180°-40°
=140°
AOC=BOD(Vertically opposite angles)
AOC=40°
AOD=BOC(Vertically opposite angles)
AOD=140°
Angle BOD+angle BOC=180°
angle BOC=180°-Angle BOD
BOC=180°-40°
=140°
AOC=BOD(Vertically opposite angles)
AOC=40°
AOD=BOC(Vertically opposite angles)
AOD=140°
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