Find the measure of smallest and largest angles of triangle whose ratio of angles is 2:3:4
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let the angles of triangle be 2x, 3x, 4x
2x+3x+4x=180(angle sum property of triangle)
9x=180
x=180\9
x=20
2x=40
3x=60
4x=80
2x+3x+4x=180(angle sum property of triangle)
9x=180
x=180\9
x=20
2x=40
3x=60
4x=80
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Let the angles be taken as x.
Therefore,
2x+3x+4x=180°
⇒9x=180°
⇒x=180°÷9
=20°
Therefore the angles are as follows:
2x=2×20=40°
3x=3×20=60°
4x=4×20=80°
The largest angle is angle 4.
The smallest is angle 2.
Therefore,
2x+3x+4x=180°
⇒9x=180°
⇒x=180°÷9
=20°
Therefore the angles are as follows:
2x=2×20=40°
3x=3×20=60°
4x=4×20=80°
The largest angle is angle 4.
The smallest is angle 2.
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