Question

find the measure of teach angle of a triangle when two angles are equal and the third angle is greater than each of these angles by 30

Answer 1

Answer:

Let the angles be x∘,x∘ and x+30∘.

Then,

x+x+(x+30∘)=180∘⇒3x+30∘=180∘⇒x=50∘

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Answer 2

Answer:

Two angles are equal then let them both be x

Third angle is greater than both of them by 30 then let it be x+30

According to the angle sum property of triangle

<a+<b+<c=180

so, x+x+x+30=180

3x+30=180

3x=180-30

3x=150

x=150/3

x=50

hence the angles are 50,50,80