Question

find the measure of the angles of a parallelogram whose one angle is 60 degree more than twice its adjacent angles​

Answer 1

Answer:in a parallelogram sum of adjacent angles is 180degrees.

Let A and B are two adjacent angles

A=x, B=2x+60

A+B=180degrees

x+2x+60=180

3x+60=180

3x=180-60

3x=120

x=120/3

so, x=40degrees

Therefore,

A=2x+60

A=140 degrees

B=x

B=40degrees

Angle C=120degrees, Angle D=40

Step-by-step explanation: