Find the measure of the side of a rhombus if it's diagonal measure 35cm and 28cm
Answers
Answered by
4
Let the side be x,
As we know that diagonals of rhombus bisects each other by 90°,
By Pythagoras theorem,
(35/2)² +(28/2)² =side²
1225/4 +14² =side²
(1224 +196)/4 =side²
1420/4 =side²
√{1420/4} =side
√355 =side
18.84 =side
I hope this will help you
-by ABHAY
As we know that diagonals of rhombus bisects each other by 90°,
By Pythagoras theorem,
(35/2)² +(28/2)² =side²
1225/4 +14² =side²
(1224 +196)/4 =side²
1420/4 =side²
√{1420/4} =side
√355 =side
18.84 =side
I hope this will help you
-by ABHAY
Answered by
3
Let the side be x cm.
As we know that diagonals of rhombus bisects each other by 90° as said first. By Pythagoras theorem,
(35/2)² +(28/2)² =side²
1225/4 +14² =side²
(1224 +196)/4 =side²
1420/4 =side²
√{1420/4} =side
√355 =side
18.84 =side
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
As we know that diagonals of rhombus bisects each other by 90° as said first. By Pythagoras theorem,
(35/2)² +(28/2)² =side²
1225/4 +14² =side²
(1224 +196)/4 =side²
1420/4 =side²
√{1420/4} =side
√355 =side
18.84 =side
I hope the answer was helpful to you If it was please mark it as brainlist ❤️
Similar questions