Question

Find the measure of the side of a rhombus if its diagonals measure 35 cm and 28 cm.​

Answer 1

Answer:

Let ABCD be a rhom. with O as intersection of diagonals.

And we know that diagonal bisect each other

>OA=1/2AD=35/2=17.5

>OB=1/2BC=28/2=14

By Pythagoras Theorem

AB^2=OA^2+OB^2

AB^2=17.5^2+14^2

AB^2=502.25

AB=√502.25

AB=22.14

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Answer 2

the measurement of the side of a rhombus is 22.1

cm