Question

Find the measure of the side of Rhombus. If its diagonals measures 12 cm and 16 cm.​

Answer 1

Step-by-step explanation:

Let ABCD be the rhombus and AC and BD bisect at point O. AC = 16cm and BD = 12cm.

⇒  We know that the diagonals of rhombus bisect at right angles.

⇒  AO=  

2

16

​  

=8cm

⇒  BO=  

2

12

​  

=6cm

⇒  In right angled △AOB,

By using Pythagoras theorem,

⇒  AB  2

=AO  

2

+BO  

2

 

⇒  AB  

2

=8  

2

+6  

2

 

⇒  AB  

2

=64+36

⇒  AB  

2

=100

⇒  AB=  

100

​  

 

⇒  AB=10cm

∴  Side of a rhombus is 10cm.  

Answer 2

Step-by-step explanation:

Area of rhombus=1/2×d1 ×d2

½× 12×16

12×8

96cm²