Find the measures of the angle of a triangle in each of the follwing case:
(i) One of the angles is 140° and the other two angles are equal.
[HINT. Let x be the measure of the smallest angle in degrees. Then measures of the other two angles are 2x and 3x.]
(ii) If one angle of a triangle is 80° and the other two angles are in the ratio 3:7
(iii) The angles are in the ratio 2 : 3 : 4.
PLEASE ANSWER ALL 3 QUESTIONS PLEASEEEEEEEEEEEEEEEEEE..........
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Answer:20 degreesStep-by-step explanation:sum of all the angles of triangle is 180 degrees
2) 3x+7x+80 = 180 degrees
10x = 180-80 = 100 degrees
x= 100/10 = 10
3x= 3*10= 30 degrees
7x = 7*10 = 70 degrees
3) 2x+3x+4x = 180 degrees
9x = 180
x= 180/9= 20
2x= 2*20= 40 degrees
3x=3*20= 60 degrees
4x= 4*20 = 80 degrees
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