Question

Find the measures of the angles of the ∆ABC if m∠A : m∠B : m∠C = 2:3:4.

Answer 1

$\huge\bigstar\sf\red{Answer:}$

$\textsf{Let the constant be n.}$

$\sf{\therefore{\angle A+\angle B+\angle C=180}}$

$\sf{...sum of all angles of triangle is 180^\circ}$

$\sf{\therefore{2n+3n+4n=180}}$

$\sf{\therefore{9n=180}}$

$\sf{\therefore{n=\dfrac{180}{9}}}$

$\sf{\therefore{n=20}}$

$\sf{The \ angles \ are:}$

$\sf{\angle A=2n=2(20)=40^\circ,}$

$\sf{\angle B=3n=3(20)=60^\circ,}$

$\sf{\angle C=4n=4(20)=80^\circ.}$