Question

Find the mechanical energy of block spring system having a spring constant of 1.3 N/cm and amplitude of

2.4 cm​

Answer 1

Answer:

3.744x10^-2 J

Explanation:

equation for energy stored in a spring block system,

PE=1/2kx^2

therefore,E=1/2 x 1.3 x 2.4 x 2.4

                 =3.744J x 10^-2(unit is centiJ)

Answer 2

Given,

K=1.3N/cm(1m=100cm)

=1.3/100=0.013N/m

A=2.4cm

=2.4/100=0.024m

E=1/2×kV^2

E=(1/2)×0.013×(0.024)^2

=3.744×10^-6J

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