Question

find the median from the following table: Marks: 0_10, 10_20, 20_30, 30_40, 40_50. no. of students: 8, 30, 40, 12, 10? Describe this question and solutions. iska answer 23 aa rha h​

Answer 1

Answer:

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Answer 2

answer

here , CI(class intervals) = mArks , f(frequency)= no. of studentS)

and cf(cumulative frequency)

CI f cf

0-10 8 8

10-20 30 38 (30+80

20-30 40 78 (38 +40)

30-40 12 90 (78 + 12)

40-50 10 100 (90 +10)

n =100

n/2 = 50 (for findinG tHe median class)

as , we need to look up for a CF which has a number = or just greater than n/2

therefore,

median class = 20---30

l = 20 , h = 10 , cfo = 38 , f = 40

now, we know that

median = l+ (\frac{\frac{n}{2}-cfo}{f}) * hmedian=l+(

f

2

n

−cfo

)∗h

on substituting the values, we get

= 20+ (\frac{50 - 38}{40} }) * 10

= 20+ (\frac{12}{4}})

= 20+ 3=20+3

= 23

median = 23